Calculate the Volume of a Gas at Standard Temperature

Explanation:

Given data:

Initial temperature = 9°C (9+273 = 282 K)

Initial volume of gas = 6.17 L

Final volume of gas = ?

Final temperature = standard = 273 K

Solution:

Formula:

The Charles Law will be applied to solve the given problem. According to this law, 'the volume of a given amount of gas is directly proportional to its temperature at a constant number of moles and pressure'.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume

T₂ = Final temperature

Now we will put the values in the formula:

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁

V₂ = 6.17 L × 273 K / 282 K

V₂ = 1684.41 L.K / 282 K

V₂ = 5.97 L

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