How many moles of AlCl3 are there in 1.81 x 10^14 molecules of AlCl3 ?

Calculation of Moles of AlCl3

Given:

Number of molecules of AlCl3 = 1.81 x 10^14

Molar mass of AlCl3 = 133.34 g/mol

Calculation:

Number of moles = Number of molecules / Avogadro's number

Number of moles = 1.81 x 10^14 / 6.022 × 10^23

Number of moles ≈ 0.3 x 10^-9 moles

Therefore, there are approximately 0.3 x 10^-9 moles of AlCl3 in 1.81 x 10^14 molecules of AlCl3.