Molarity Calculation for Phosphoric Acid Solution

What is the molarity of phosphoric acid in a solution labelled 20% of Phosphoric acid by weight and a density of 1.12g/mL?

What is the definition of molarity in chemistry?

How do you calculate the number of moles of solute in a solution?

The molarity of phosphoric acid in a solution labelled 20% of Phosphoric acid by weight and a density of 1.12g/mL is 11.85 mol/L.

Molarity is the concentration unit in chemistry measured in moles per liter (mol/L).

Molarity is an important concept in chemistry that helps to quantify the concentration of a solution. In this case, we are calculating the molarity of phosphoric acid in a solution that is labeled as 20% phosphoric acid by weight and has a density of 1.12g/mL.

The first step in calculating the molarity is to determine the number of moles of phosphoric acid in the solution. We can do this by using the formula:

Number of moles = Mass / Molar mass

Given that the mass is 20% of the solution and the molar mass of phosphoric acid is 98:

Number of moles = 20 / 98 = 0.204 moles

Next, we need to calculate the volume of the solution using the density:

Volume = Mass / Density

Volume = 20 / 1.12 = 17.85 ml

Now, we can calculate the molarity using the formula:

Molarity (M) = Number of moles / Volume

Plugging in the values we have:

M = 0.204 / 17.85 * 1000 / 1 = 11.85 mol/L

Therefore, the molarity of phosphoric acid in the solution is 11.85 mol/L.