Mole Calculation Practice Exercise: How many moles of oxygen are in 1.6 mol of Ca(NO3)2?

What is the mole ratio between Ca(NO3)2 and O2?

Choose the correct answer:

a. 1.6 mol

b. 3.2 mol

c. 4.8 mol

d. 9.6 mol

Final answer:

To find the number of moles of oxygen in 1.6 mol of Ca(NO3)2, use the mole ratio between Ca(NO3)2 and O2.

Explanation:

To determine the number of moles of oxygen in 1.6 mol of Ca(NO3)2, we need to use the mole ratio between Ca(NO3)2 and O2. The formula of Ca(NO3)2 tells us that there are 2 moles of O in every 1 mole of Ca(NO3)2. Therefore, we can calculate:

O2 moles = 1.6 mol Ca(NO3)2 × 2 mol O / 1 mol Ca(NO3)2 = 3.2 mol

Therefore, there are 3.2 mol of oxygen in 1.6 mol of Ca(NO3)2.

← New volume calculation for air in syringe Moles of oxygen in methyl tert butyl ether sample →

More Posts: