Moles Calculation for Magnesium Nitrate

How to calculate the number of moles in a sample of magnesium nitrate?

A 1.36-g sample of magnesium nitrate, Mg(NO3)2, contains ________ mol of this compound.

Answer:

Magnesium nitrate contains 0.0091 mol.

The question is asking how many moles of magnesium nitrate are contained in a 1.36 g sample of the compound. This requires understanding and applying the concept of molar mass.

The molar mass of magnesium nitrate (Mg(NO3)2) is 148.32 g/mol. To find moles, we use the formula: moles = mass / molar mass. Plugging the values: moles = 1.36 g / 148.32 g/mol = 0.00916 mol.

Therefore, a 1.36 g sample of magnesium nitrate contains 0.00916 mol of the compound.

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