What Percentage of Heat Released by Rock was Absorbed by Water?

How do I determine the percentage of heat absorbed by the water?

Determining Heat Released by the Rock:

• Mass of rock (M) = 40 g
• Initial temperature of rock (T₁) = 100 °C
• Final temperature of rock (T₂) = 40 °C
• Change in temperature of rock (ΔT) = 40 - 100 = -60 °C
• Specific heat capacity of rock (C) = 0.84 J/gºC

Q = MCΔT

Q = 40 × 0.84 × -60

Q = -2016 J

Determining Heat Absorbed by the Water:

• Volume of water (V) = 45 mL
• Mass of water (M) = 45 g
• Initial temperature of water (T₁) = 30 °C
• Final temperature of water (T₂) = 40 °C
• Change in temperature of water (ΔT) = 40 - 30 = 10 °C
• Specific heat capacity of water (C) = 4.186 J/gºC

Q = MCΔT

Q = 45 × 4.186 × 10

Q = 1883.7 J

Calculating Percentage of Heat Absorbed by Water:

• Heat released by rock = 2016 J
• Heat absorbed by water = 1883.7 J

Percentage of heat absorbed = (Heat absorbed by water / Heat released) × 100

Percentage of heat absorbed = (1883.7 / 2016) × 100

Percentage of heat absorbed = 93.4%