A Ball Kicked from with Initial Velocity m/s
Velocity Calculation
A) The velocity of the ball 0.3 seconds after being kicked is calculated using the Momentum Principle. The velocity will be v(0.3) = (8, 0 , 9.943).
Average Velocity
B) The average velocity of the ball over the time interval is calculated. The average velocity will be 21.1 m/s.
Location Calculation
C) Using the average velocity, the location of the ball 0.5 seconds after being kicked is found to be S(0.5) = (4, 9.5 , 9.72625).
Equations Information
Given equations:
- s(0) = 8i + 0j -7k
- v(0) = -8i +19j -3k
- a(t) = 0i+0j-9.81k
Explanation
(a) To find the velocity of the ball 0.3 seconds after being kicked, use the Momentum Principle. Calculate velocity using the initial velocity and acceleration due to gravity.
(b) Calculate the average velocity of the ball over the time interval by dividing the displacement by the time interval.
(c) Use the average velocity to find the location of the ball 0.5 seconds after being kicked by multiplying with time interval.
What is the velocity of the ball 0.3 seconds after being kicked? What is the average velocity of the ball over this time interval? Use the average velocity to find the location of the ball 0.5 seconds after being kicked.
The velocity of the ball 0.3 seconds after being kicked is <-8, 16.06, -3> m/s. The average velocity of the ball over this time interval is <0, 53.53, 13.33> m/s. The location of the ball 0.5 seconds after being kicked is <8, 26.765, -0.335> m.