Domestic Power Load Calculation: Total Current and Energy Consumption

What is the total current taken from the supply of 230 V for a domestic power load consisting of various appliances? How can we calculate the energy consumed in a day if only a quarter of the load persists all the time?

The total current taken from the supply for a domestic power load can be calculated by adding up the power ratings of all the appliances and using the formula I = P / V. To calculate the energy consumed in a day, we need to determine the average load that persists all the time and then multiply it by the time. The total current taken from the supply is 15.41 A, while the energy consumed in a day is 21.27 kWh.

Total Current Calculation

The domestic power load in a house consists of 4 lamps, 6 fans, 2 refrigerators, and 2 heaters. To calculate the total current taken from the supply of 230 V, we first need to determine the power consumed by each appliance.
  • Lamps: 4 lamps of 900 W each consume a total power of 4 * 80 W = 320 W.
  • Fans: 6 fans of 80 W each consume a total power of 6 * 80 W = 480 W.
  • Refrigerators: 2 refrigerators of 1/2 hp consume a total power of 2 * 1/2 hp = 745.7 W.
  • Heaters: 2 heaters of 1000 W each consume a total power of 2 * 1000 W = 2000 W.
By adding up the total power consumed by all appliances, we get 320 W + 480 W + 745.7 W + 2000 W = 3545.7 W. Using the formula I = P / V, the total current taken from the supply is 3545.7 W / 230 V = 15.41 A.

Energy Consumption Calculation

To calculate the energy consumed in a day, we need to find the average load that persists all the time. Considering only a quarter of the total load persists, the average load is 1/4 * 3545.7 W = 886.43 W. Converting the power to kilowatts, we get 886.43 W / 1000 = 0.88643 kW. Multiplying the power with time, the energy consumed in a day is 0.88643 kW * 24 hours = 21.27 kWh. Therefore, the energy consumed in a day under these conditions is 21.27 kWh.
← Exploring the relationship between energy and motion Calculating percentage error in voltage measurement →

More Posts: