Energy Consumption Calculation: Let's Do the Math!

What is the energy consumed by a resistive coil in 100 seconds?

The peak power consumed by a resistive coil when connected to an AC source is 80W. Find the energy consumed by the coil in 100 sec in kJ.

Answer:

The energy consumed by the coil in 100 seconds is 7.992 kJ.

To calculate the energy consumed by a resistive coil connected to an AC source, we need to use the formula for determining energy which is E = Pt. In this case, the power consumed by the coil is 80W, and the time is 100 seconds.

Converting the time from seconds to hours, we get 100 sec = 100/3600 h = 0.0278 h. Substituting the values into the formula, we have E = Pt = (80W)(0.0278h) = 2.22 Wh.

To convert watt-hours to kilojoules, we use the conversion factor 1 Wh = 3.6 kJ. Thus, E = (2.22 Wh)(3.6 kJ/Wh) = 7.992 kJ. Therefore, the energy consumed by the coil in 100 seconds is 7.992 kJ.