How does replacing a 60 W light bulb with a 120 W light bulb affect brightness?
What happens when a student replaces a 60 W light bulb with a 120 W light bulb in terms of resistance and current?
When a student replaces a 60 W light bulb with a 120 W light bulb, the 120 W light bulb will have more resistance and draw more current compared to the 60 W light bulb. Correct?
Explanation:
When a student replaces a 60 W light bulb with a 120 W light bulb, the 120 W light bulb will have less resistance and draw more current compared to the 60 W light bulb.
The power consumed by a bulb is given by the equation P = V^2/R, where P is the power, V is the voltage, and R is the resistance. Since the student is using the same voltage for both bulbs, the power rating (in Watts) is directly proportional to the resistance. A higher wattage bulb will have a lower resistance, and vice versa. Therefore, the 120 W bulb will have less resistance than the 60 W bulb.
Moreover, Ohm's law states that current (I) is directly proportional to voltage (V) and inversely proportional to resistance (R) (I = V/R). If the resistance decreases, the current will increase, assuming the voltage remains constant. So, the 120 W bulb will draw more current than the 60 W bulb.
To summarize, when the student replaces the 60 W bulb with the 120 W bulb, the 120 W bulb will have less resistance and draw more current, resulting in increased brightness.