How Far Can a Ball Travel When Kicked at an Angle of 40 Degrees?

What is the initial velocity and angle of the ball when kicked?

The ball is kicked at an angle of 40 degrees with the ground with the initial velocity of 15m/s.

How long does it take for the ball to reach point B?

The ball reaches point B after 1.5 seconds.

What is the horizontal distance the ball travels before reaching point B?

The ball travels a horizontal distance of 17.235 meters before reaching point B.

Answers:

The initial velocity of the ball is 15m/s and it is kicked at an angle of 40 degrees with the ground.

It takes the ball 1.5 seconds to reach point B.

The ball travels a horizontal distance of 17.235 meters before reaching point B.

When a ball is kicked at an angle of 40 degrees with the ground and has an initial velocity of 15 m/s, it reaches point B after 1.5 seconds. To find the horizontal distance traveled (range), we can use the equation R = Vx * t, where R is the range, Vx is the horizontal component of velocity (11.49 m/s), and t is the time taken (1.5 seconds).

Plugging in the values, we get R = 11.49 * 1.5 = 17.235 meters. The ball moves at a constant velocity of 11.49 m/s in the horizontal direction. In the vertical direction, the ball moves with an initial velocity of 9.645 m/s and experiences a downward acceleration due to gravity.

← Discovering the power of magnifying glass Vector v magnitude and direction angle →