How far does a car travel during a 2.0-second interval?

When a car goes from an initial speed of 16 meters per second to a complete stop in 2.0 seconds, we can calculate the distance it travels using the equations of uniformly accelerated motion. In this case, the car is decelerating to reach a full stop, meaning it is experiencing negative acceleration.

We can use the following kinematic equation to determine the distance traveled by the car: x = ut + 0.5at², where:
x = distance traveled
u = initial velocity = 16 m/s
t = time taken = 2.0 seconds
a = acceleration

First, we need to calculate the acceleration of the car. Since the car is decelerating, the final speed is 0 m/s. We can use the equation v = u + at to find the acceleration:
a = (v - u) ÷ t
a = (0 - 16) ÷ 2
a = -8 m/s²

Now, we substitute the values of initial velocity, time, and acceleration into the distance equation to find the distance traveled by the car:
x = ut + 0.5at²
x = (16 * 2) + 0.5 * (-8) * (2)²
x = 16 meters

Therefore, the car travels 16 meters during the 2.0-second interval, which corresponds to option (B) in the given choices.