How to Calculate the Magnitude of Electric Field in an Excimer Laser Tube

What is the formula to calculate the magnitude of the electric field in the electrical discharge produced in the excimer laser tube?

Given that the voltage was 8.0kV and the distance was 4.0 mm, what is the magnitude of the electric field?

Select the correct option:

A. 2.0 × 10⁶ V/m
B. 4.0 × 10⁵ V/m
C. 6.0 × 10⁴ V/m
D. 8.0 × 10³ V/m

Answer

The correct option is A. The magnitude of the electric field in the electrical discharge produced in the excimer laser tube is 2.0 × 10⁶ V/m.

An electric field is a physical field that surrounds electrically charged particles and acts as an attractor or repellent to all other charged particles in the vicinity. Electric field is measured in Volts per meter (V/m).

The magnitude of the electric field in the electrical discharge produced in the excimer laser tube can be calculated using the formula:

E = V/d

Where E is the electric field, V is the voltage (8000 V), and d is the distance (4.0 mm).

Substitute the values into the formula:

E = 8000 V / (4.0 mm)

Electric field = 2.0 × 10⁶ V/m

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