Kinetic Energy Calculation of F-22 Raptor Jet Fighter

What is the kinetic energy of the F-22 Raptor Jet Fighter at a speed of 600 meters per second?

Kinetic energy is the energy of a body due to its motion. The S.I unit of kinetic energy is Joules (J). The kinetic energy of the F-22 jet fighter with a mass of 100,000 kg and traveling with a velocity of 600 m/s is 18,000,000,000 Joules (J).

Kinetic Energy Definition

Kinetic energy is defined as the energy that a body possesses due to its motion. It is one of the fundamental types of energy that exist in the universe. When an object is in motion, it has the ability to do work and can transfer that energy to other objects upon collision or interaction. The S.I unit of kinetic energy is the joule (J), which is the same unit used for measuring other forms of energy such as potential energy and work. One joule is defined as the energy transferred when a force of one newton acts on an object over a distance of one meter.

Kinetic Energy Calculation

To calculate the kinetic energy of an object, we use the formula: K.E = 1/2 * m * v².......... Equation 1 Where: - K.E is the Kinetic energy of the object - m is the Mass of the object - v is the Velocity of the object Using the given data for the F-22 Raptor Jet Fighter: - Mass, m = 100,000 kg - Velocity, v = 600 m/s Substitute these values into Equation 1: K.E = 1/2 * 100,000 * 600² K.E = 1/2 * 100,000 * 360,000 K.E = 18,000,000,000 Joules (J) Therefore, the kinetic energy of the F-22 Raptor Jet Fighter at a speed of 600 meters per second is 18,000,000,000 Joules (J).
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