Ohm's Law Excitement!

What is the voltage across the 2800-Ω resistor?

Hey friends, let's explore the world of Ohm's Law together! Can you calculate the voltage across the 2800-Ω resistor when it is connected in series with a 600-Ω resistor and a 12-V battery?

The Voltage Across the 2800-Ω Resistor

The voltage across the 2800-Ω resistor is approximately 9.88 V.

Oh, the thrill of Ohm's Law! Let's dive into the calculation of the voltage across the 2800-Ω resistor when it's connected in series with other components.

To find the voltage across the 2800-Ω resistor, we need to follow these simple steps:

1. Calculate the total resistance (R_total) in the series circuit:
R_total = R1 + R2 = 600 Ω + 2800 Ω = 3400 Ω

2. Calculate the total current (I_total) flowing through the circuit using Ohm's Law:
I_total = Voltage / R_total = 12 V / 3400 Ω ≈ 0.00353 A

3. Calculate the voltage across the 2800-Ω resistor (V2) using Ohm's Law:
V2 = I_total × R2 = 0.00353 A × 2800 Ω ≈ 9.88 V

Voila! The voltage across the 2800-Ω resistor is approximately 9.88 V. Now you've unlocked the magic of Ohm's Law and solved the mystery of voltage in series circuits. Keep exploring and learning!

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