Probability Mass Function (pmf) of Bernoulli Distribution

What is the probability mass function for a Bernoulli distribution with probability of success p = 0.3?

Choose one:

A. (0.7)^x * (0.3)(1-2) for x = 0,1

B. (0.3)^x * (0.7)^(1-x) for x = 0,1

C. (0.3)^(0.7)(2-1) for x = 0,1

D. (0.3)^(0.7)(n-1) for x = 0,1,2,...,n

Answer:

The correct probability mass function for a Bernoulli distribution with probability of success p = 0.3 is B. (0.3)^x * (0.7)^(1-x) for x = 0,1.

A Bernoulli distribution is a discrete probability distribution that models a single experiment with two possible outcomes: success (with probability p) and failure (with probability 1-p). The probability mass function (pmf) of a Bernoulli distribution gives the probability of each possible outcome.

For a Bernoulli distribution with probability of success p, the pmf is given by Of(x) = p^x * (1-p)^(1-x), where x is the outcome (either 0 or 1).

In the given distribution, the probability of success is p = 0.3. Therefore, the pmf for this distribution is: Of(x) = (0.3)^x * (0.7)^(1-x) for x = 0,1.