Reflection on the Concept of Acceleration in Motion

How can we calculate the final velocity and distance traveled by a car accelerating uniformly?

Given that a car starts from rest and accelerates at a rate of 2m/s^2 for 15 seconds, how can we determine its final velocity and the distance it covers?

Final answer:

The final velocity of the car, given the constant acceleration and time period, is 30 m/s. Also, the car would travel a distance of 225m during this time.

The subject matter of this question pertains to the concepts of velocity and acceleration. We can solve this problem using specific equations from the laws of motion.

(a) The final velocity of the car can be calculated using the formula v = u + at, where 'v' is the final velocity, 'u' is the initial velocity, 'a' is acceleration, and 't' is the time. Given that the car starts from rest (u = 0), acceleration (a) = 2m/s^2, and time (t) = 15 seconds. So, the final velocity would be v = 0 + (2m/s^2 * 15s) = 30 m/s.

(b) The distance traveled can be calculated using the formula s = ut + 1/2at^2 where 's' is the displacement (or distance traveled in this context). Again, given that the car starts from rest (u = 0), acceleration (a) = 2m/s^2, and time (t) = 15 seconds. Therefore, the distance traveled would be s = 0 + 1/2*(2m/s^2) *(15s) ^2 = 225m.