Students Catapult Contest: How High Does the Ball Go?

Students Catapult Contest

Students were having a catapult contest, launching a tennis ball with their home built devices. The winner launched a ball at 30 degrees from the ground at 6.0 m/s.

Calculating the Maximum Height

Question: How high does the ball go?

Answer: The height reached by the ball = 0.459 m

Explanation:

We are given that θ = 30 degrees

Initial speed, u = 6 m/s

We have to find the maximum height reached by the ball.

Maximum height reached by ball: h = (u^2sin^2θ) / (2g)

Where g = 9.8 m/s^2

Substitute the values: h = (6^2sin^230 degrees) / (2 * 9.8)

h = (36 * 1/4) / (2 * 9.8)

h = 0.459 m

Hence, the height reached by the ball = 0.459 m

Students were having a catapult contest, launching a tennis ball with their home built devices. The winner launched a ball at 30 degrees from the ground at 6.0 m/s. How high does the ball go?

The height reached by the ball = 0.459 m Explanation: We are given that θ = 30 degrees. Initial speed, u = 6 m/s. We have to find the maximum height reached by the ball. Maximum height reached by ball: h = (u^2sin^2θ) / (2g). Where g = 9.8 m/s^2. Substitute the values: h = (6^2sin^230 degrees) / (2 * 9.8). h = (36 * 1/4) / (2 * 9.8). h = 0.459 m. Hence, the height reached by the ball = 0.459 m