You are called as an expert witness to analyze the following auto accident
Analysis of Auto Accident
a) What was the speed of car A just before the collision?
b) If the speed limit was 35mph, was car A speeding, and if so, by how many miles per hour was it exceeding the speed limit?
c) Explain why we can classify the collision as completely inelastic
d) Calculate the total kinetic energy before and after the collision
a) What was the speed of car A just before the collision? b) If the speed limit was 35mph, was car A speeding, and if so, by how many miles per hour was it exceeding the speed limit? c) Explain why we can classify the collision as completely inelastic d) Calculate the total kinetic energy before and after the collisiona). va=17.23 πs or 38.54 mph b). v=38.54 mph and limit is 35 mph c). Completely inelastic d). Eka=192.967 kJ Ekt=76.071 kJ Explanation: ππ=1300kg ππ=2000kg π₯π=7.25m π’π=0.65 The motion is an inelastic collision so ππ*π£π+ππ*π£π=(ππ+ππ)*π£π The force of the motion is contrarest by the force of friction so F-Fπ’π=0 F=Fπ’π Fπ’π=π’π*π*π F=m*a a=Fm a=πΉπ’ππ a=π’π*π a=0.65*9.89.8ππ 2 a=6.39ππ 2 Now with the acceleration can find the time and the velocity final that make the distance 7.25m being united π₯π=π₯π+π£π*π‘+2*π*π‘2 π₯π=0 π£π=0 π₯π=2*π*π‘2 π‘2=π₯π2*π π‘=π πππ‘7288π6.39ππ 2 π‘=1.06s So the velocity final can be find using this time π£π=π£π+π*π‘ π£π=0 π£π=6.39ππ 2*1.06π π£π=6.79 ππ